"""流程发布前的处理器身份、版本与保护路径合同。"""

import pytest

from muse.任务运行.接口 import 步骤处理器, 步骤结果, 步骤计划
from muse.编排.接口 import 流程定义, 流程校验错误, 流程登记


def 构造登记() -> 流程登记:
    登记 = 流程登记()
    登记.登记处理器(
        步骤处理器("guard", "1", lambda _: 步骤结果({}), "v1", "v1", 保护职责="来源校验")
    )
    登记.登记处理器(步骤处理器("work", "1", lambda _: 步骤结果({}), "v1", "v1"))
    登记.登记类型("example", 必需保护=("来源校验",))
    return 登记


def test_未知处理器与保护绕行拒绝__a50001() -> None:
    登记 = 构造登记()
    with pytest.raises(流程校验错误):
        登记.冻结(流程定义("example", "1", (步骤计划("s1", "/tmp/script.py", "1"),)))
    with pytest.raises(流程校验错误, match="保护"):
        登记.冻结(
            流程定义(
                "example", "1", (步骤计划("guard", "guard", "1"), 步骤计划("work", "work", "1"))
            )
        )
    计划 = 登记.冻结(
        流程定义(
            "example",
            "1",
            (步骤计划("guard", "guard", "1"), 步骤计划("work", "work", "1", ("guard",))),
        )
    )
    assert 计划.流程ID == "example"


def test_流程依赖环与不兼容槽位拒绝__a50002() -> None:
    登记 = 构造登记()
    with pytest.raises(流程校验错误, match="环"):
        登记.冻结(
            流程定义(
                "example",
                "1",
                (步骤计划("g", "guard", "1", ("w",)), 步骤计划("w", "work", "1", ("g",))),
            )
        )
    登记.登记处理器(步骤处理器("incompatible", "1", lambda _: 步骤结果({}), "v2", "v2"))
    with pytest.raises(流程校验错误, match="合同"):
        登记.冻结(
            流程定义(
                "example",
                "1",
                (步骤计划("g", "guard", "1"), 步骤计划("w", "incompatible", "1", ("g",))),
            )
        )